下面是一段多线程的示例代码

#!/usr/bin/python3  
  
import?_thread  
import?time  
  
#?为线程定义一个函数  
def?print_time(?threadName,?delay):  
???count?=?0  
???while?count?<?5:  
??????time.sleep(delay)  
??????count?+=?1  
??????print?("%s:?%s"?%?(?threadName,?time.ctime(time.time())?))  
  
#?创建两个线程  
try:  
???_thread.start_new_thread(?print_time,?("Thread-1",?2,?)?)  
???_thread.start_new_thread(?print_time,?("Thread-2",?4,?)?)  
except:  
???print?("Error:?无法启动线程")  
  

我想实现的是

a = [ "Thread-%s" % i for i in range(100)]

10个线程同时打印，打印完即止

同理多进程中应该怎么实现

多进程建议使用：multiprocessing模块

# -*- coding:utf-8 -*-
import  os
from multiprocessing import Pool

class MultiProcess(object):

    def __init__(self, process_count):
        self.__process_count = process_count

    def multi_process(self, obj_name, fun_name, fun_args):
        fun = getattr(obj_name, fun_name)
        print('Parent process %s.' % os.getpid())
        pool = Pool(self.__process_count)
        print(obj_name, fun_name, fun_args)
        for fun_arg in fun_args:
            print(fun_arg)
            pool.apply_async(fun, args=fun_arg)
        print('Waiting for all subprocesses done...')
        pool.close()
        pool.join()
        print('All subprocesses done.')

class A():
    def num_test(self, nums):
        print([num for num in range(nums)])

    def run(self):
        MultiProcess(2).multi_process(A, "num_test", [(self, 9,), (self, 5,)])

if __name__ == "__main__":
    A().run()
    # MultiProcess(2).multi_process(A, "num_test", [(None, 9,), (None, 5,)])