问题描述

如何生成数组包数组的格式的数据,将pointa数组中的location元素取出，并弄成数字类型，放入新的数组

我的数据
`
"points": [{

    "accuracy": 37.52,
    "direction": 0,
    "height": 175.47,
    "locatetime": 1593320683164,
    "location": "120.374254,36.088865",
    "speed": 0
    },
    {
    "accuracy": 36.448,
    "direction": 0,
    "height": 175.46,
    "locatetime": 1593320685163,
    "location": "120.374254,36.088865",
    "speed": 0
    },
    {
    "accuracy": 32.16,
    "direction": 0,
    "height": 175.43,
    "locatetime": 1593320687164,
    "location": "120.374254,36.088865",
    "speed": 0
    }]
 `
    

###想要的数据类型
`
[

[120.23, 26.45],
[120.23, 26.45],
[120.23, 26.45],
[120.23, 26.45],

]
`

points.map(v => v.location.split(',').map(k=>Number(k)))

//输出
 [
     [120.374254, 36.088865]
     [120.374254, 36.088865]
     [120.374254, 36.088865]
 ]

函数式编程，拿走不谢

points.map(point => point.location.split(",").map(n => Number(n)))

points.map(item => item.location).map(item => item.split(',').map(t => Number(t)))

const result = points.map(item => {
    // 如果需要精确到小数点后两位，使用tofixed，并再数字化即可，具体可看demo
  return item.location.split(',').map(every => Number(every))
})

demo 链接

let point = []
points.map(item=>{
  let arr = []
  arr.push(item.location)
  point.push(arr)
})