// 根据obj1中name字段里的值删除obj2，如何实现？
上面这个是试题，意思也不太懂，我的理解是去重，如果不是这个意思求指出。
下面是我的解题方法，请问有没有更好的方法。不敢相信这么简单

   
   let obj1 = [{
        name:'tao'
    },{
        name:'tao2'
    },{
        name:'tao3'
    }]

    let obj2 = [{
        name:'tao'
    },{
        name:'tao2'
    },{
        name:'tao4'
    }]
    
    let newArr = [];
    let a = obj1.map(x=>x.name)
    obj2.map((x,i)=>{
        if (!a.includes(x.name)) {
            console.log(1,x.name)
            newArr.push(x)
        }
    })
    console.log(newArr)

let obj1 = [{
        name:'tao'
    },{
        name:'tao2'
    },{
        name:'tao3'
    }]

    let obj2 = [{
        name:'tao'
    },{
        name:'tao2'
    },{
        name:'tao4'
    }]
    
var names = obj1.reduce((res,item) => (res.add(item.name), res), new Set());

obj2 = obj2.filter(v => !names.has(v.name));
console.log(obj2)